What are the solutions to the equation 5x^2-29x+20=0 ?

The solutions to the equation 5x^2-29x+20=0 are x=5,x= 4/5

Find the zeros of 5x^2-29x+20=0

The zeros of 5x^2-29x+20=0 are x=5,x= 4/5

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5 x^{2} - 29 x + 20 = 0

x = 5, x = \frac{4}{5}

Decimal Notation

x = 5, x = 0.8

Solution steps

5 x^{2} - 29 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 29 ) \pm ( - 29 ) ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

(- 29)^{2} - 4 \cdot 5 \cdot 20 = 21

x_{1, 2} = \frac{- ( - 29 ) \pm 21}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 29 ) + 21}{2 \cdot 5}, x_{2} = \frac{- ( - 29 ) - 21}{2 \cdot 5}

x = \frac{- ( - 29 ) + 21}{2 \cdot 5} : 5

x = \frac{- ( - 29 ) - 21}{2 \cdot 5} : \frac{4}{5}

The solutions to the quadratic equation are:

x = 5, x = \frac{4}{5}

2 x^{2} = - 7 x - 9

2 x^{2} = - 7 x + 4

4 v^{2} = 9

(x + 1)^{2} - 8 (x + 1) - 9 = 0

2 x - 2 x^{2} = - 7

What are the solutions to the equation 5x^2-29x+20=0 ?
The solutions to the equation 5x^2-29x+20=0 are x=5,x= 4/5
Find the zeros of 5x^2-29x+20=0
The zeros of 5x^2-29x+20=0 are x=5,x= 4/5