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受欢迎的代数 >

-x^2+40x-1200=0

解答

- x^{2} + 40 x - 1200 = 0

解答

x = 20 - 202 i, x = 20 + 202 i

求解步骤

- x^{2} + 40 x - 1200 = 0

使用求根公式求解

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 1 ) ( - 1200 )}{2 ( - 1 )}

化简

4 0^{2} - 4 (- 1) (- 1200) : 402 i

x_{1, 2} = \frac{- 40 \pm 40 2 i}{2 ( - 1 )}

将解分隔开

x_{1} = \frac{- 40 + 40 2 i}{2 ( - 1 )}, x_{2} = \frac{- 40 - 40 2 i}{2 ( - 1 )}

x = \frac{- 40 + 40 2 i}{2 ( - 1 )} : 20 - 202 i

x = \frac{- 40 - 40 2 i}{2 ( - 1 )} : 20 + 202 i

二次方程组的解是:

x = 20 - 202 i, x = 20 + 202 i

作图

流行的例子

\frac{1}{7} x^{2} - 3 = 4

solvefor x,y=x^2-20x

so l v e f or x, y = x^{2} - 20 x

3x^2+14x-1=7x-3

3 x^{2} + 14 x - 1 = 7 x - 3

3x^2+10x+20=10-3x

3 x^{2} + 10 x + 20 = 10 - 3 x

solvefor x,f(x+2)=4x^2+3

so l v e f or x, f (x + 2) = 4 x^{2} + 3