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人気のある代数 >

solvefor x,0=x(1-x)+m-hx

解

解く

x, 0 = x (1 - x) + m - h x

解

x = - \frac{- 1 + h + ( 1 - h ) ^{2} + 4 m}{2}, x = - \frac{- 1 + h - ( 1 - h ) ^{2} + 4 m}{2}

解答ステップ

0 = x (1 - x) + m - h x

拡張

x (1 - x) + m - h x : x - x^{2} + m - x h

0 = x - x^{2} + m - x h

辺を交換する

x - x^{2} + m - x h = 0

標準的な形式で書く

a x^{2} + b x + c = 0

- x^{2} + (1 - h) x + m = 0

解くとthe二次式

x_{1, 2} = \frac{- ( 1 - h ) \pm ( 1 - h ) ^{2} - 4 ( - 1 ) m}{2 ( - 1 )}

簡素化

(1 - h)^{2} - 4 (- 1) m : (1 - h)^{2} + 4 m

x_{1, 2} = \frac{- ( 1 - h ) \pm ( 1 - h ) ^{2} + 4 m}{2 ( - 1 )}

解を分離する

x_{1} = \frac{- ( 1 - h ) + ( 1 - h ) ^{2} + 4 m}{2 ( - 1 )}, x_{2} = \frac{- ( 1 - h ) - ( 1 - h ) ^{2} + 4 m}{2 ( - 1 )}

x = \frac{- ( 1 - h ) + ( 1 - h ) ^{2} + 4 m}{2 ( - 1 )} : - \frac{- 1 + h + ( 1 - h ) ^{2} + 4 m}{2}

x = \frac{- ( 1 - h ) - ( 1 - h ) ^{2} + 4 m}{2 ( - 1 )} : - \frac{- 1 + h - ( 1 - h ) ^{2} + 4 m}{2}

二次equationの解:

x = - \frac{- 1 + h + ( 1 - h ) ^{2} + 4 m}{2}, x = - \frac{- 1 + h - ( 1 - h ) ^{2} + 4 m}{2}

グラフ

人気の例

6x^2-5x+4=4(3x^2-2x+1)

6 x^{2} - 5 x + 4 = 4 (3 x^{2} - 2 x + 1)

solvefor t,h=-16t^2+v^0t+h^0

so l v e f or t, h = - 16 t^{2} + v^{0} t + h^{0}

7 x^{2} + 8 x - 3 = 0

- x^{2} + 7 x = 10

14 = w (2 w - 3)