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受欢迎的代数 >

solvefor t,h=-16t^2+v^0t+h^0

解答

求解

t, h = - 16 t^{2} + v^{0} t + h^{0}

解答

t = - \frac{- 1 + - 64 h + 65}{32}, t = - \frac{- 1 - - 64 h + 65}{32}

求解步骤

h = - 16 t^{2} + v^{0} t + h^{0}

整理后得

h = - 16 t^{2} + t + 1

交换两边

- 16 t^{2} + t + 1 = h

将

h

para o lado esquerdo

- 16 t^{2} + t + 1 - h = 0

使用求根公式求解

t_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 16 ) ( 1 - h )}{2 ( - 16 )}

化简

1^{2} - 4 (- 16) (1 - h) : - 64 h + 65

t_{1, 2} = \frac{- 1 \pm - 64 h + 65}{2 ( - 16 )}

将解分隔开

t_{1} = \frac{- 1 + - 64 h + 65}{2 ( - 16 )}, t_{2} = \frac{- 1 - - 64 h + 65}{2 ( - 16 )}

t = \frac{- 1 + - 64 h + 65}{2 ( - 16 )} : - \frac{- 1 + - 64 h + 65}{32}

t = \frac{- 1 - - 64 h + 65}{2 ( - 16 )} : - \frac{- 1 - - 64 h + 65}{32}

二次方程组的解是:

t = - \frac{- 1 + - 64 h + 65}{32}, t = - \frac{- 1 - - 64 h + 65}{32}

作图

流行的例子

7 x^{2} + 8 x - 3 = 0

- x^{2} + 7 x = 10

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