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受欢迎的代数 >

(2x-1)(2x+1)=(2x-3)2

解答

(2 x - 1) (2 x + 1) = (2 x - 3) 2

解答

x = \frac{1}{2} + i, x = \frac{1}{2} - i

求解步骤

(2 x - 1) (2 x + 1) = (2 x - 3) \cdot 2

展开

(2 x - 1) (2 x + 1) : 4 x^{2} - 1

展开

(2 x - 3) \cdot 2 : 4 x - 6

4 x^{2} - 1 = 4 x - 6

将

6

para o lado esquerdo

4 x^{2} + 5 = 4 x

将

4 x

para o lado esquerdo

4 x^{2} + 5 - 4 x = 0

改写成标准形式

a x^{2} + b x + c = 0

4 x^{2} - 4 x + 5 = 0

使用求根公式求解

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 4 \cdot 5}{2 \cdot 4}

化简

(- 4)^{2} - 4 \cdot 4 \cdot 5 : 8 i

x_{1, 2} = \frac{- ( - 4 ) \pm 8 i}{2 \cdot 4}

将解分隔开

x_{1} = \frac{- ( - 4 ) + 8 i}{2 \cdot 4}, x_{2} = \frac{- ( - 4 ) - 8 i}{2 \cdot 4}

x = \frac{- ( - 4 ) + 8 i}{2 \cdot 4} : \frac{1}{2} + i

x = \frac{- ( - 4 ) - 8 i}{2 \cdot 4} : \frac{1}{2} - i

二次方程组的解是:

x = \frac{1}{2} + i, x = \frac{1}{2} - i

作图

流行的例子

solvefor x,f^1(x)=x^2+2

so l v e f or x, f^{1} (x) = x^{2} + 2

2 y (y + 5) - 5 = 0

y^{2} + 18 y - 40 = 0

completesquare x^2+6x=55

co m pl e t es q u a re x^{2} + 6 x = 55

k (k - 1) = 12