What are the solutions to the equation 4x^2+24x+43=0 ?

The solutions to the equation 4x^2+24x+43=0 are x=-3+i(sqrt(7))/2 ,x=-3-i(sqrt(7))/2

Find the zeros of 4x^2+24x+43=0

The zeros of 4x^2+24x+43=0 are x=-3+i(sqrt(7))/2 ,x=-3-i(sqrt(7))/2

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4 x^{2} + 24 x + 43 = 0

x = - 3 + i \frac{7}{2}, x = - 3 - i \frac{7}{2}

Solution steps

4 x^{2} + 24 x + 43 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 24 \pm 2 4 ^{2} - 4 \cdot 4 \cdot 43}{2 \cdot 4}

Simplify

2 4^{2} - 4 \cdot 4 \cdot 43 : 47 i

x_{1, 2} = \frac{- 24 \pm 4 7 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 24 + 4 7 i}{2 \cdot 4}, x_{2} = \frac{- 24 - 4 7 i}{2 \cdot 4}

x = \frac{- 24 + 4 7 i}{2 \cdot 4} : - 3 + i \frac{7}{2}

x = \frac{- 24 - 4 7 i}{2 \cdot 4} : - 3 - i \frac{7}{2}

The solutions to the quadratic equation are:

x = - 3 + i \frac{7}{2}, x = - 3 - i \frac{7}{2}

(x - 2) (x + 2) = 12

5 x^{2} + 3 x = 2 x^{2} - 9 x

9 (x + 6)^{2} - 7 = 18

1760 - 0.08 X^{2} + 0.1 X^{2} = 2080

14 = - 2.7 t^{2} + 50 t + 6.5

What are the solutions to the equation 4x^2+24x+43=0 ?
The solutions to the equation 4x^2+24x+43=0 are x=-3+i(sqrt(7))/2 ,x=-3-i(sqrt(7))/2
Find the zeros of 4x^2+24x+43=0
The zeros of 4x^2+24x+43=0 are x=-3+i(sqrt(7))/2 ,x=-3-i(sqrt(7))/2