3^x=7^{x+2}

Lösung

3^{x} = 7^{x + 2}

x = \frac{2 ln ( 7 )}{ln ( 3 ) - ln ( 7 )}

Dezimale

x = - 4.59321 \dots

Schritte zur Lösung

3^{x} = 7^{x + 2}

Wende Exponentenregel an

x ln (3) = (x + 2) ln (7)

Löse

x ln (3) = (x + 2) ln (7) : x = \frac{2 ln ( 7 )}{ln ( 3 ) - ln ( 7 )}

x = \frac{2 ln ( 7 )}{ln ( 3 ) - ln ( 7 )}

2^{x - 3} + 2^{x - 1} + 2^{x} = 52

3 6^{x} + 4 2^{x} = 4 9^{x}

5 \cdot 1 8^{6 x} = 26

5^{x} = 4

6^{x} = 216