2=14^{x+2}

Lösung

2 = 1 4^{x + 2}

x = \frac{ln ( 2 )}{ln ( 14 )} - 2

Dezimale

x = - 1.73735 \dots

Schritte zur Lösung

2 = 1 4^{x + 2}

Wende Exponentenregel an

ln (2) = (x + 2) ln (14)

Löse

ln (2) = (x + 2) ln (14) : x = \frac{ln ( 2 )}{ln ( 14 )} - 2

x = \frac{ln ( 2 )}{ln ( 14 )} - 2

- x^{2} e^{- x} + 5 x e^{- x} = 0

3^{2 x + 2} + 3 (3^{x}) - 2 = 0

5^{x - 3} = 137

1 0^{2 x^{2} + 2 x} = 10 0^{- 6 x + 8}

(2 e)^{(x^{2} - 2)} = 4