4^{3x+1}=8^{x-1}

Lösung

4^{3 x + 1} = 8^{x - 1}

x = - \frac{5}{3}

Dezimale

x = - 1.66666 \dots

Schritte zur Lösung

4^{3 x + 1} = 8^{x - 1}

Wende Exponentenregel an

2 (3 x + 1) = 3 (x - 1)

Löse

2 (3 x + 1) = 3 (x - 1) : x = - \frac{5}{3}

x = - \frac{5}{3}

9^{2 x - 3} = 27

4 \cdot 3^{4 x + 1} = 2

e^{2 x} - 8 e^{x} + 12 = 0

\frac{1}{2} = 2^{x}

8 (e)^{2 x + 1} = 4