4^{2x+1}=3^{x-2}

Lösung

4^{2 x + 1} = 3^{x - 2}

x = - \frac{2 ln ( 6 )}{4 ln ( 2 ) - ln ( 3 )}

Dezimale

x = - 2.14072 \dots

Schritte zur Lösung

4^{2 x + 1} = 3^{x - 2}

Wende Exponentenregel an

(2 x + 1) ln (4) = (x - 2) ln (3)

Löse

(2 x + 1) ln (4) = (x - 2) ln (3) : x = - \frac{2 ln ( 6 )}{4 ln ( 2 ) - ln ( 3 )}

x = - \frac{2 ln ( 6 )}{4 ln ( 2 ) - ln ( 3 )}

a^{a} = 2

1800 = 900 (1 + 0.06)^{X}

8 = 3 (5)^{x}

so l v e f or t, x = e^{- 3 t}

4^{x} + 9 \cdot 2^{x} + 23 = 0