2^{x-3}=5

Lösung

2^{x - 3} = 5

x = \frac{ln ( 5 )}{ln ( 2 )} + 3

Dezimale

x = 5.32192 \dots

Schritte zur Lösung

2^{x - 3} = 5

Wende Exponentenregel an

(x - 3) ln (2) = ln (5)

Löse

(x - 3) ln (2) = ln (5) : x = \frac{ln ( 5 )}{ln ( 2 )} + 3

x = \frac{ln ( 5 )}{ln ( 2 )} + 3

9 (5^{x}) = 8^{x + 4}

5^{6 x + 1} - 6 \cdot 5^{3 x} + 1 = 0

3^{x} - 3^{1 - x} = 2

e^{x} = e^{4 - x}

\frac{3 ^{x}}{9 ^{2 x + 3}} = 1