7^{6x+7}=2

Lösung

7^{6 x + 7} = 2

x = \frac{ln ( 2 ) - 7 ln ( 7 )}{6 ln ( 7 )}

Dezimale

x = - 1.10729 \dots

Schritte zur Lösung

7^{6 x + 7} = 2

Wende Exponentenregel an

(6 x + 7) ln (7) = ln (2)

Löse

(6 x + 7) ln (7) = ln (2) : x = \frac{ln ( 2 ) - 7 ln ( 7 )}{6 ln ( 7 )}

x = \frac{ln ( 2 ) - 7 ln ( 7 )}{6 ln ( 7 )}

x + 5 = 5^{x}

2^{3 x - 1} = \frac{1}{2}

2 e^{2 x} + 5 e^{x} - 3 = 0

so l v e f or x, x y = e^{4 x - y} - 1

(\frac{2}{3})^{x} = \frac{4}{9}