\sqrt[5]{5}=25^x

Lösung

55 = 2 5^{x}

x = \frac{1}{10}

Dezimale

x = 0.1

Schritte zur Lösung

55 = 2 5^{x}

Wende Exponentenregel an

\frac{1}{5} = 2 x

Löse

\frac{1}{5} = 2 x : x = \frac{1}{10}

x = \frac{1}{10}

2^{x} = 3^{(x - 1)}

\frac{1}{3} = 3^{(2 x + 2)}

4^{x} + 64 = 16 \cdot 2^{x}

so l v e f or b, e^{a x} - e^{b - a x} = c

5^{5 x - 2} = 40