1/3 =3^{(2x+2)}

Lösung

\frac{1}{3} = 3^{(2 x + 2)}

x = - \frac{3}{2}

Dezimale

x = - 1.5

Schritte zur Lösung

\frac{1}{3} = 3^{(2 x + 2)}

Wende Exponentenregel an

- 1 = 2 x + 2

Löse

- 1 = 2 x + 2 : x = - \frac{3}{2}

x = - \frac{3}{2}

4^{x} + 64 = 16 \cdot 2^{x}

so l v e f or b, e^{a x} - e^{b - a x} = c

5^{5 x - 2} = 40

10 e^{- 0.03 x} = 4

3^{x} + \frac{2}{3 ^{x - 1}} = 5