5^{5x-4}=(1/5)^{x+1}

Lösung

5^{5 x - 4} = (\frac{1}{5})^{x + 1}

x = \frac{1}{2}

Dezimale

x = 0.5

Schritte zur Lösung

5^{5 x - 4} = (\frac{1}{5})^{x + 1}

Wende Exponentenregel an

5 x - 4 = - (x + 1)

Löse

5 x - 4 = - (x + 1) : x = \frac{1}{2}

x = \frac{1}{2}

100 = 2 e^{\frac{3}{x}}

64 = 4^{2 x - 3}

6 (10)^{x} + (10)^{x - 1} = 2

so l v e f or x, 5^{2 x - 5} = 125

e^{2 x} - 14 = 5 e^{x}