2^{2x}=n+1

Lösung

2^{2 x} = n + 1

x = \frac{ln ( n + 1 )}{2 ln ( 2 )}

Schritte zur Lösung

2^{2 x} = n + 1

Wende Exponentenregel an

2 x ln (2) = ln (n + 1)

Löse

2 x ln (2) = ln (n + 1) : x = \frac{ln ( n + 1 )}{2 ln ( 2 )}

x = \frac{ln ( n + 1 )}{2 ln ( 2 )}

2^{4 x - 1} = 3^{5 - 2 x}

2^{4 x + 3} = 6

e^{2 x} + 42 = - 13 e^{x}

2^{3 x + 1} \cdot 8^{x - 1} = 128

e^{3 - 2 x} = 8 - 3 x