2^{4x+3}=6

Lösung

2^{4 x + 3} = 6

x = \frac{ln ( \frac{3}{4} )}{4 ln ( 2 )}

Dezimale

x = - 0.10375 \dots

Schritte zur Lösung

2^{4 x + 3} = 6

Wende Exponentenregel an

(4 x + 3) ln (2) = ln (6)

Löse

(4 x + 3) ln (2) = ln (6) : x = \frac{ln ( \frac{3}{4} )}{4 ln ( 2 )}

x = \frac{ln ( \frac{3}{4} )}{4 ln ( 2 )}

e^{2 x} + 42 = - 13 e^{x}

2^{3 x + 1} \cdot 8^{x - 1} = 128

e^{3 - 2 x} = 8 - 3 x

2^{4 x + 3} = 512

so l v e f or a, ln (x^{(2 - a)}) = 4