2^nsqrt(2)=\sqrt[3]{4^n}

Lösung

2^{n} 2 = 3 4^{n}

n = - \frac{3}{2}

Dezimale

n = - 1.5

Schritte zur Lösung

2^{n} 2 = 3 4^{n}

Wende Exponentenregel an

n + \frac{1}{2} = \frac{2}{3} n

Löse

n + \frac{1}{2} = \frac{2}{3} n : n = - \frac{3}{2}

n = - \frac{3}{2}

e^{m x} + x e^{m x} = 0

4^{(x - 2)} = \frac{4 x}{16}

4^{x - 5} = 32

3^{x + 1} + 3 = 30

4^{x + 4} = 1 6^{3 x - 4}