3^{x+2}=9^{x-1}

Lösung

3^{x + 2} = 9^{x - 1}

x = 4

Schritte zur Lösung

3^{x + 2} = 9^{x - 1}

Wende Exponentenregel an

x + 2 = 2 (x - 1)

Löse

x + 2 = 2 (x - 1) : x = 4

x = 4

2^{x + 1} = \frac{1}{2}

\frac{2 ^{x^{2}}}{2 ^{x + 6}} = 1

3 \cdot 2^{4 x} + 2^{2 x} - 10 = 0

8^{3 x - 5} = 4^{x + 3}

\frac{x}{e ^{3 - 2 x}} = 4