What are the solutions to the equation 4x^4+25x^2+36=0 ?

The solutions to the equation 4x^4+25x^2+36=0 are x= 3/2 i,x=-3/2 i,x=2i,x=-2i

Find the zeros of 4x^4+25x^2+36=0

The zeros of 4x^4+25x^2+36=0 are x= 3/2 i,x=-3/2 i,x=2i,x=-2i

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4 x^{4} + 25 x^{2} + 36 = 0

x = \frac{3}{2} i, x = - \frac{3}{2} i, x = 2 i, x = - 2 i

Solution steps

4 x^{4} + 25 x^{2} + 36 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

4 u^{2} + 25 u + 36 = 0

Solve

4 u^{2} + 25 u + 36 = 0 : u = - \frac{9}{4}, u = - 4

u = - \frac{9}{4}, u = - 4

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = - \frac{9}{4} : x = \frac{3}{2} i, x = - \frac{3}{2} i

Solve

x^{2} = - 4 : x = 2 i, x = - 2 i

The solutions are

x = \frac{3}{2} i, x = - \frac{3}{2} i, x = 2 i, x = - 2 i

- 4 = x^{5} - 5 x

x, x^{3} + y^{3} = 2

x^{3} - 3 x^{2} + 3 x + 1 = 0

x^{3} - x^{2} - 2 = 0

x^{3} - 5 x + 1 = - 0.8

What are the solutions to the equation 4x^4+25x^2+36=0 ?
The solutions to the equation 4x^4+25x^2+36=0 are x= 3/2 i,x=-3/2 i,x=2i,x=-2i
Find the zeros of 4x^4+25x^2+36=0
The zeros of 4x^4+25x^2+36=0 are x= 3/2 i,x=-3/2 i,x=2i,x=-2i