What are the solutions to the equation x^4-x^3-x^2+x=0 ?

The solutions to the equation x^4-x^3-x^2+x=0 are x=0,x=1,x=-1

Find the zeros of x^4-x^3-x^2+x=0

The zeros of x^4-x^3-x^2+x=0 are x=0,x=1,x=-1

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x^{4} - x^{3} - x^{2} + x = 0

x = 0, x = 1, x = - 1

Solution steps

x^{4} - x^{3} - x^{2} + x = 0

Factor

x^{4} - x^{3} - x^{2} + x : x (x - 1)^{2} (x + 1)

x (x - 1)^{2} (x + 1) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x = 0 or x - 1 = 0 or x + 1 = 0

Solve

x - 1 = 0 : x = 1

Solve

x + 1 = 0 : x = - 1

The solutions are

x = 0, x = 1, x = - 1

2 x^{3} - 6 x^{2} = 56 x

3 y^{3} = 375

2 x (x + 9) (x^{2} - 2) = 0

2 x^{3} - 4 x + 5 = 0

10 x^{4} - 9 x^{2} + 2 = 0

What are the solutions to the equation x^4-x^3-x^2+x=0 ?
The solutions to the equation x^4-x^3-x^2+x=0 are x=0,x=1,x=-1
Find the zeros of x^4-x^3-x^2+x=0
The zeros of x^4-x^3-x^2+x=0 are x=0,x=1,x=-1