(b^3)/3 =-1/3

Lösung

\frac{b ^{3}}{3} = - \frac{1}{3}

b = - 1, b = \frac{1}{2} - \frac{3}{2} i, b = \frac{1}{2} + \frac{3}{2} i

Schritte zur Lösung

\frac{b ^{3}}{3} = - \frac{1}{3}

Multipliziere beide Seiten mit

3

b^{3} = - 1

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

b = 3 - 1, b = 3 - 1 \frac{- 1 + 3 i}{2}, b = 3 - 1 \frac{- 1 - 3 i}{2}

3 - 1 = - 1

Vereinfache

3 - 1 \frac{- 1 + 3 i}{2} : \frac{1}{2} - \frac{3}{2} i

Vereinfache

3 - 1 \frac{- 1 - 3 i}{2} : \frac{1}{2} + \frac{3}{2} i

b = - 1, b = \frac{1}{2} - \frac{3}{2} i, b = \frac{1}{2} + \frac{3}{2} i

5 x^{3} - 7 x^{2} + 4 x - 8 = 0

2 x^{4} - 4 x^{3} - 4^{2} + 6 x + 9 = 0

x^{3} + 20 x^{2} + 64 x - 100 = 0

- 3 x (36 x^{2} - 25) (x^{2} - 2) = 0

x^{3} - 14 x^{2} = + 56 - 64