m^3=2

Lösung

m^{3} = 2

m = 32, m = - 32 \frac{1}{2} + 32 \frac{3}{2} i, m = - 32 \frac{1}{2} - 32 \frac{3}{2} i

Schritte zur Lösung

m^{3} = 2

Für

x^{3} = f (a)

sind die Lösungen

x = 3 f (a), 3 f (a) \frac{- 1 - 3 i}{2}, 3 f (a) \frac{- 1 + 3 i}{2}

m = 32, m = 32 \frac{- 1 + 3 i}{2}, m = 32 \frac{- 1 - 3 i}{2}

Vereinfache

32 \frac{- 1 + 3 i}{2} : - 32 \frac{1}{2} + 32 \frac{3}{2} i

Vereinfache

32 \frac{- 1 - 3 i}{2} : - 32 \frac{1}{2} - 32 \frac{3}{2} i

m = 32, m = - 32 \frac{1}{2} + 32 \frac{3}{2} i, m = - 32 \frac{1}{2} - 32 \frac{3}{2} i

- x^{3} + x^{2} + 14 x + 11 = 0

2 x^{2} x - 3 x - 20 = 0

(x - 1)^{6} + (x - 2)^{6} = 1

so l v e f or y, x = (y - 1)^{3}

4 x^{3} - 7 x^{2} - 2 x = 0