What is the answer to solvefor x,log_{e}(2x-1)=-3 ?

The answer to solvefor x,log_{e}(2x-1)=-3 is x=(1+e^3)/(2e^3)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

solvefor x,log_{e}(2x-1)=-3

solve for

x, lo g_{e} (2 x - 1) = - 3

x = \frac{1 + e ^{3}}{2 e ^{3}}

Decimal Notation

x = 0.52489 \dots

Solution steps

lo g_{e} (2 x - 1) = - 3

Apply log rules

2 x - 1 = \frac{1}{e ^{3}}

Solve

2 x - 1 = \frac{1}{e ^{3}} : x = \frac{1 + e ^{3}}{2 e ^{3}}

x = \frac{1 + e ^{3}}{2 e ^{3}}

lo g_{2} (- 5 x + 8) = 1

1.5 n^{2} - 7.5 n lo g_{10} (n) = 0

6 ln (5 x - 3) + 12 = 0

(1 - ln (x)) d x = 0

ln (c x^{7}) = 7 ln (c) + 7 ln (x)

What is the answer to solvefor x,log_{e}(2x-1)=-3 ?
The answer to solvefor x,log_{e}(2x-1)=-3 is x=(1+e^3)/(2e^3)