solvefor x,f=ln(x+f)

Lösung

löse nach

x, f = ln (x + f)

x = e^{f} - f

Schritte zur Lösung

f = ln (x + f)

Wende die log Regel an

e^{f} = x + f

Löse

e^{f} = x + f : x = e^{f} - f

x = e^{f} - f

ln (16 + x^{2}) = - ln (16 - x^{2})

32 = \frac{50}{ln ( q + 1 )}

ln (7 x) = 1

lo g_{10} (3 - 2 x) = 1

ln (x) - ln (5) = 0