x^2-7x+9yi=y^2i+20i-12

解答

x^{2} - 7 x + 9 y i = y^{2} i + 20 i - 12

x = 3, x = 3, x = 4, x = 4, y = 5 y = 4 y = 5 y = 4

求解步骤

x^{2} - 7 x + 9 y i = y^{2} i + 20 i - 12

将

y^{2} i + 20 i - 12

改写成标准复数形式:

- 12 + (y^{2} + 20) i

x^{2} - 7 x + 9 y i = - 12 + (y^{2} + 20) i

复数仅在实部和虚部均相等时才相等改写为方程组:

[x^{2} - 7 x = - 12 9 y = y^{2} + 20]

[x^{2} - 7 x = - 12 9 y = y^{2} + 20] : x = 3, x = 3, x = 4, x = 4, y = 5 y = 4 y = 5 y = 4

x = 3, x = 3, x = 4, x = 4, y = 5 y = 4 y = 5 y = 4

18 i + 3 x = (9 y) i

25 x^{2} + b = (5 x + 8 i) (5 x - 8 i)

z^{2} + 2 z + 1 - 2 i = 0

z^{2} - (5 - 2 i) z + (3 - 15 i) = 0

8 + (3 x + y) i = 2 x - 4 i