z=(c-2i)/(2-i)

Lösung

z = \frac{c - 2 i}{2 - i}

z = \frac{2 + 2 c}{5} + i \frac{- 4 + c}{5}

Schritte zur Lösung

z = \frac{c - 2 i}{2 - i}

Schreibe

z

in der Standard komplexen Form um:

x + y i

Schreibe

\frac{c - 2 i}{2 - i}

um:

\frac{2 + 2 c}{5} + i \frac{- 4 + c}{5}

z = \frac{2 + 2 c}{5} + i \frac{- 4 + c}{5}

\frac{z + 2}{z - 2} = 3 + i^{27}

∣ z ∣^{2} + 1 + 12 i = 6 z

(x + y i)^{2} = - 7 + 24 i

z^{2} - 5 z + 4 + 10 i = 0

9 + 12 i = 3 x + 4