((2+ai))/(1+i)=real

解答

\frac{( 2 + ai )}{1 + i} = re a l

a = 2, r = \frac{1}{e l}, r \neq = 0, l \neq = 0

求解步骤

\frac{( 2 + ai )}{1 + i} = re a l

在两边乘以

1 + i

\frac{2 + ai}{1 + i} (1 + i) = re a l (1 + i)

乘开

2 + ia = e l a r + e i l a r

复数仅在实部和虚部均相等时才相等改写为方程组:

[2 = e l a r a = e l a r]

[2 = e l a r a = e l a r] : a = 2, r = \frac{1}{e l}, r \neq = 0, l \neq = 0

a = 2, r = \frac{1}{e l}, r \neq = 0, l \neq = 0

2 x^{2} = 14 x - 30 i

s i f (x) = - 2 x + 5, E (s, x) = f (1) + f (- 1)

3 z^{2} + (2 - 3 i) z - 1 - 3 i = 0

r (t) = (2 t + 1) i + (t^{2} - 1) j

2 x + 51 = 4 (2 + y i) - 12