y=in(2x),y,y=1,y=6

解答

y = in (2 x), y, y = 1, y = 6

x = 0, y = 0

求解步骤

y = in (2 x)

将

y

改写成标准复数形式:

y + 0 i

y + 0 i = in (2 x)

将

in (2 x)

改写成标准复数形式:

0 + 2 n x i

y + 0 i = 0 + 2 n x i

复数仅在实部和虚部均相等时才相等改写为方程组:

[y = 0 0 = 2 n x]

[y = 0 0 = 2 n x] : x = 0, y = 0

x = 0, y = 0

x^{2} - 2 x + i = 0

y i n^{0} = 3 y^{2} + x - 1

\frac{s i}{P ( x )} = (x - 1)^{2} + x - 1

(z - \frac{3}{5})^{2} + (5 i)^{2} = 0

- i = x^{2} - y^{2} + 2 x y i