x^2-7x+9yi=y^2i+20yi-12

解

x^{2} - 7 x + 9 y i = y^{2} i + 20 y i - 12

x = 3, x = 3, x = 4, x = 4, y = 0 y = - 11 y = 0 y = - 11

解答ステップ

x^{2} - 7 x + 9 y i = y^{2} i + 20 y i - 12

標準的な複素数形式で

y^{2} i + 20 y i - 12

を書き換える:

- 12 + (y^{2} + 20 y) i

x^{2} - 7 x + 9 y i = - 12 + (y^{2} + 20 y) i

複素数は, その実数部と虚数部が等しい場合にのみ等しくなるequation系として書き換える:

[x^{2} - 7 x = - 12 9 y = y^{2} + 20 y]

[x^{2} - 7 x = - 12 9 y = y^{2} + 20 y] : x = 3, x = 3, x = 4, x = 4, y = 0 y = - 11 y = 0 y = - 11

x = 3, x = 3, x = 4, x = 4, y = 0 y = - 11 y = 0 y = - 11