solvefor x,kx^2+36x+k=0

解答

x, k x^{2} + 36 x + k = 0

x = \frac{- 18 + - k ^{2} + 324}{k}, x = - \frac{- k ^{2} + 324 + 18}{k}; k \neq = 0

求解步骤

k x^{2} + 36 x + k = 0

使用求根公式求解

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 kk}{2 k}

化简

3 6^{2} - 4 kk : 2 324 - k^{2}

x_{1, 2} = \frac{- 36 \pm 2 324 - k ^{2}}{2 k}; k \neq = 0

将解分隔开

x_{1} = \frac{- 36 + 2 324 - k ^{2}}{2 k}, x_{2} = \frac{- 36 - 2 324 - k ^{2}}{2 k}

x = \frac{- 36 + 2 324 - k ^{2}}{2 k} : \frac{- 18 + - k ^{2} + 324}{k}

x = \frac{- 36 - 2 324 - k ^{2}}{2 k} : - \frac{- k ^{2} + 324 + 18}{k}

二次方程组的解是:

x = \frac{- 18 + - k ^{2} + 324}{k}, x = - \frac{- k ^{2} + 324 + 18}{k}; k \neq = 0

so l v e f or y, x^{2} - 2 x y + 1 - 3 y^{2} = 0

co m pl e t es q u a re x^{2} + 4 x + 7 = 5

x^{2} - 6 x = \frac{1}{2} x + 42

5 n = 2 n^{2} - 3

\frac{( x + 6 ) ^{2}}{2} = 8