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受欢迎的代数 >

4a^2x^2+8ax+3=0

解答

4 a^{2} x^{2} + 8 a x + 3 = 0

解答

x = - \frac{1}{2 a}, x = - \frac{3}{2 a}; a \neq = 0

求解步骤

4 a^{2} x^{2} + 8 a x + 3 = 0

使用求根公式求解

x_{1, 2} = \frac{- 8 a \pm ( 8 a ) ^{2} - 4 \cdot 4 a ^{2} \cdot 3}{2 \cdot 4 a ^{2}}

化简

(8 a)^{2} - 4 \cdot 4 a^{2} \cdot 3 : 4 a

x_{1, 2} = \frac{- 8 a \pm 4 a}{2 \cdot 4 a ^{2}}; a \neq = 0

将解分隔开

x_{1} = \frac{- 8 a + 4 a}{2 \cdot 4 a ^{2}}, x_{2} = \frac{- 8 a - 4 a}{2 \cdot 4 a ^{2}}

x = \frac{- 8 a + 4 a}{2 \cdot 4 a ^{2}} : - \frac{1}{2 a}

x = \frac{- 8 a - 4 a}{2 \cdot 4 a ^{2}} : - \frac{3}{2 a}

二次方程组的解是:

x = - \frac{1}{2 a}, x = - \frac{3}{2 a}; a \neq = 0

作图

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