4^{2x}=7

Lösung

4^{2 x} = 7

x = \frac{ln ( 7 )}{4 ln ( 2 )}

Dezimale

x = 0.70183 \dots

Schritte zur Lösung

4^{2 x} = 7

Wende Exponentenregel an

2 x ln (4) = ln (7)

Löse

2 x ln (4) = ln (7) : x = \frac{ln ( 7 )}{4 ln ( 2 )}

x = \frac{ln ( 7 )}{4 ln ( 2 )}

e^{x} x^{2} (x^{2} + x - 6) = 0

so l v e f or t, E^{- 18 t} = \frac{15}{4}

6 (2^{3 x - 1}) - 7 = 9

3^{x + 2} - 5 \times 3^{x} = 36

e^{7 x} = 2