2x^2+22x+60=0

解

2 x^{2} + 22 x + 60 = 0

x = - 5, x = - 6

解答ステップ

2 x^{2} + 22 x + 60 = 0

解くとthe二次式

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 2 \cdot 60}{2 \cdot 2}

2 2^{2} - 4 \cdot 2 \cdot 60 = 2

x_{1, 2} = \frac{- 22 \pm 2}{2 \cdot 2}

解を分離する

x_{1} = \frac{- 22 + 2}{2 \cdot 2}, x_{2} = \frac{- 22 - 2}{2 \cdot 2}

x = \frac{- 22 + 2}{2 \cdot 2} : - 5

x = \frac{- 22 - 2}{2 \cdot 2} : - 6

二次equationの解:

x = - 5, x = - 6