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Problemas populares de Álgebra
ln(9x)+3=ln(3x+2)
\ln(9x)+3=\ln(3x+2)
log_{a}(4)=1.585
\log_{a}(4)=1.585
4=ln(5x+e)-1
4=\ln(5x+e)-1
log_{10}(3x+2)=log_{10}(x-1)
\log_{10}(3x+2)=\log_{10}(x-1)
log_{3}(8x)-4log_{3}(2)=0
\log_{3}(8x)-4\log_{3}(2)=0
log_{2}(x-5)-log_{2}(x+5)=5
\log_{2}(x-5)-\log_{2}(x+5)=5
log_{10}(2-x)=3
\log_{10}(2-x)=3
-ln(x-1)=2
-\ln(x-1)=2
2log_{3}(x+4)=log_{3}(9)+2
2\log_{3}(x+4)=\log_{3}(9)+2
log_{5}(x+1)=12
\log_{5}(x+1)=12
log_{5}(x)-log_{5}(14)=3
\log_{5}(x)-\log_{5}(14)=3
log_{10}(2)(log_{3}(x))=-1
\log_{10}(2)(\log_{3}(x))=-1
2log_{10}(x)-3=5
2\log_{10}(x)-3=5
solvefor x,log_{9}(x)=2
solvefor\:x,\log_{9}(x)=2
log_{b}(1)=1
\log_{b}(1)=1
log_{6}(x^2)2log_{6}(x)=1
\log_{6}(x^{2})2\log_{6}(x)=1
0=log_{2}(5-x)
0=\log_{2}(5-x)
ln(x)= a/3+1
\ln(x)=\frac{a}{3}+1
log_{2}(x+5)=5-log_{2}(x)
\log_{2}(x+5)=5-\log_{2}(x)
solvefor x,fx=log_{10}(x-3)
solvefor\:x,fx=\log_{10}(x-3)
log_{10}(6-2x)=1+log_{10}(x)
\log_{10}(6-2x)=1+\log_{10}(x)
solvefor y,x=2log_{10}(y)
solvefor\:y,x=2\log_{10}(y)
log_{10}(p^{-1})=1
\log_{10}(p^{-1})=1
log_{3}(x)+3=2
\log_{3}(x)+3=2
7.5=0.65log_{10}(0E)+1.45
7.5=0.65\log_{10}(0E)+1.45
log_{10}(X)=3.4146
\log_{10}(X)=3.4146
solvefor a,a^b=e^{bln(a)}
solvefor\:a,a^{b}=e^{b\ln(a)}
ln(x)=7.352205355
\ln(x)=7.352205355
log_{2}(x)=3-log_{2}(3x-10)
\log_{2}(x)=3-\log_{2}(3x-10)
log_{e}((760)/x)=751
\log_{e}(\frac{760}{x})=751
log_{4}(x^2+3)=2
\log_{4}(x^{2}+3)=2
log_{b}(343)=-3/2
\log_{b}(343)=-\frac{3}{2}
log_{a}(64)=2
\log_{a}(64)=2
log_{9}(2x-7)= 3/2
\log_{9}(2x-7)=\frac{3}{2}
3log_{8}(x)-log_{x}(64+1)=0
3\log_{8}(x)-\log_{x}(64+1)=0
log_{4}(x+2)+log_{4}(x-4)=2
\log_{4}(x+2)+\log_{4}(x-4)=2
ln(4x)+1=0
\ln(4x)+1=0
log_{y}(125)=-3/2
\log_{y}(125)=-\frac{3}{2}
log_{2}(x)+log_{x}(4)=3
\log_{2}(x)+\log_{x}(4)=3
7-2ln(x)=2
7-2\ln(x)=2
solvefor H,p=-log_{10}(H)
solvefor\:H,p=-\log_{10}(H)
10log_{10}(x)=3
10\log_{10}(x)=3
10log_{10}(x)=1
10\log_{10}(x)=1
2=log_{10}(4pix)-log_{10}(pi)
2=\log_{10}(4πx)-\log_{10}(π)
log_{6}(x)=0
\log_{6}(x)=0
log_{5}(4x-8)=2
\log_{5}(4x-8)=2
log_{6}(2x+3)=3
\log_{6}(2x+3)=3
0=ln(x-2)
0=\ln(x-2)
solvefor x,5log_{3}(x+11)=5
solvefor\:x,5\log_{3}(x+11)=5
log_{1/2}(x)=32^0
\log_{\frac{1}{2}}(x)=32^{0}
log_{6}(b)=5
\log_{6}(b)=5
log_{4}(3x+4)+log_{4}(16)=5
\log_{4}(3x+4)+\log_{4}(16)=5
log_{6}(x+6)=2
\log_{6}(x+6)=2
13.8=-0.008315(310.15)ln(x)
13.8=-0.008315(310.15)\ln(x)
log_{10}(8x)=-2
\log_{10}(8x)=-2
n(x)=log_{2/e}(x)
n(x)=\log_{\frac{2}{e}}(x)
ln(x)= 90/10
\ln(x)=\frac{90}{10}
log_{2}(1+a)=4
\log_{2}(1+a)=4
335=log_{93}(x)
335=\log_{93}(x)
ln(16x)=ln(16)+4ln(2)
\ln(16x)=\ln(16)+4\ln(2)
log_{3}((x+3)/2)=2
\log_{3}(\frac{x+3}{2})=2
log_{2}(x+6)-log_{2}(x-6)=3
\log_{2}(x+6)-\log_{2}(x-6)=3
0.86125=0.6446ln(x)-0.5557
0.86125=0.6446\ln(x)-0.5557
log_{2}(8x)-4log_{2}(4)=0
\log_{2}(8x)-4\log_{2}(4)=0
16=-log_{10}(x)
16=-\log_{10}(x)
4ln(6x)=12
4\ln(6x)=12
log_{4}(3x+4)=3
\log_{4}(3x+4)=3
log_{4}(3x+4)=2
\log_{4}(3x+4)=2
solvefor y,ln(y)=9t+5
solvefor\:y,\ln(y)=9t+5
solvefor y,ln(y)=6ln(x)+c
solvefor\:y,\ln(y)=6\ln(x)+c
log_{10}(x)=-8.6
\log_{10}(x)=-8.6
20*log_{10}(y)=14.63
20\cdot\:\log_{10}(y)=14.63
3log_{10}(2x+4)=x+1
3\log_{10}(2x+4)=x+1
log_{x}(9/4)=-2
\log_{x}(\frac{9}{4})=-2
solvefor x,y=ln(x-1)
solvefor\:x,y=\ln(x-1)
4ln(6x)=-4
4\ln(6x)=-4
log_{x}(9/4)=2
\log_{x}(\frac{9}{4})=2
3log_{10}(4-x)=1-x
3\log_{10}(4-x)=1-x
9/8 log_{2}(x)=-10
\frac{9}{8}\log_{2}(x)=-10
log_{a}(3)=0.565
\log_{a}(3)=0.565
log_{10}(x/3+50)=2
\log_{10}(\frac{x}{3}+50)=2
log_{10}(x/5)+3=5.3
\log_{10}(\frac{x}{5})+3=5.3
ln(sqrt(1-x))= 1/3
\ln(\sqrt{1-x})=\frac{1}{3}
50=11.936ln(x)+13.954
50=11.936\ln(x)+13.954
2log_{8}(x+5)=3
2\log_{8}(x+5)=3
log_{5}(m)=-4
\log_{5}(m)=-4
ln(x^2)=ln(10x)-3
\ln(x^{2})=\ln(10x)-3
-3=10log_{10}(x/1)
-3=10\log_{10}(\frac{x}{1})
ln(4x)-3ln(x^2)=ln(3)
\ln(4x)-3\ln(x^{2})=\ln(3)
ln(x)+ln(x+3)=0
\ln(x)+\ln(x+3)=0
log_{10}(x+5)=log_{10}(2x-3)
\log_{10}(x+5)=\log_{10}(2x-3)
ln(3x+3.7)-1.2=-12.3
\ln(3x+3.7)-1.2=-12.3
ln(x)=5.943189204
\ln(x)=5.943189204
7.53=-log_{10}(x)
7.53=-\log_{10}(x)
xln(2x)=0
x\ln(2x)=0
solvefor x,ln(x)+ln(x-7)=0
solvefor\:x,\ln(x)+\ln(x-7)=0
9=10log_{10}(x/1)
9=10\log_{10}(\frac{x}{1})
log_{343}(x)=-1/3
\log_{343}(x)=-\frac{1}{3}
log_{10}(10)+log_{10}(x-9)=1
\log_{10}(10)+\log_{10}(x-9)=1
-3x+9=log_{10}(x)
-3x+9=\log_{10}(x)
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