derivative f(x)=3x^2+x+5

Lösung

ableitung von

f (x) = 3 x^{2} + x + 5

6 x + 1

Schritte zur Lösung

\frac{d}{d x} (3 x^{2} + x + 5)

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d x}{d x} + \frac{d}{d x} (5)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d x}{d x} = 1

\frac{d}{d x} (5) = 0

= 6 x + 1 + 0

Vereinfache

= 6 x + 1

d er i v a t i v e f (x) = - 5 x^{2} + 2 x - 6

x \to 0 + lim (\frac{∣ x - 0 ∣}{0 - x})

\int_{2}^{\infty} x e^{- 4 x} d x

\int 3 e^{2 x^{3} + 3 x^{2} - 9} (x^{2} + x) d x

\frac{\partial}{\partial y} (e^{x^{2} + y^{2} - 2})