y^'+xy+4=0

Lösung

y^{^{'}} + x y + 4 = 0

y = - \frac{2 2 π erfi ( \frac{x}{2} )}{e ^{\frac{x ^{2}}{2}}} + \frac{c _{1}}{e ^{\frac{x ^{2}}{2}}}

Schritte zur Lösung

y^{'} (x) + x y + 4 = 0

Solve linear ODE:

y = - \frac{2 2 π erfi ( \frac{x}{2} )}{e ^{\frac{x ^{2}}{2}}} + \frac{c _{1}}{e ^{\frac{x ^{2}}{2}}}

y = - \frac{2 2 π erfi ( \frac{x}{2} )}{e ^{\frac{x ^{2}}{2}}} + \frac{c _{1}}{e ^{\frac{x ^{2}}{2}}}

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