derivative of tan^3(2x)

Lösung

\frac{d}{d x} (tan^{3} (2 x))

6 tan^{2} (2 x) sec^{2} (2 x)

Schritte zur Lösung

\frac{d}{d x} (tan^{3} (2 x))

Wende die Kettenregel an:

3 (tan (2 x))^{2} \frac{d}{d x} (tan (2 x))

= 3 (tan (2 x))^{2} \frac{d}{d x} (tan (2 x))

\frac{d}{d x} (tan (2 x)) = sec^{2} (2 x) \cdot 2

= 3 (tan (2 x))^{2} sec^{2} (2 x) \cdot 2

Vereinfache

= 6 tan^{2} (2 x) sec^{2} (2 x)

\int \frac{7}{2 x ^{\frac{9}{4}}} d x

y^{^{''}} - 8 y^{^{'}} + 16 y = t^{- 9} e^{4 t}

n \to \infty lim (\frac{n}{6})

\frac{\partial}{\partial y} (y e^{x y} + 2 x - 1)

\frac{\partial}{\partial x} (8 y - 4 x)