derivative y=(88t)/(99t-88)

Lösung

ableitung von

y = \frac{88 t}{99 t - 88}

- \frac{64}{( 9 t - 8 ) ^{2}}

Schritte zur Lösung

\frac{d}{d t} (\frac{88 t}{99 t - 88})

Entferne die Konstante:

(a \cdot f)^{'} = a \cdot f^{'}

= 88 \frac{d}{d t} (\frac{t}{99 t - 88})

Wende die Quotientenregel an:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= 88 \cdot \frac{\frac{d t}{d t} ( 99 t - 88 ) - \frac{d}{d t} ( 99 t - 88 ) t}{( 99 t - 88 ) ^{2}}

\frac{d t}{d t} = 1

\frac{d}{d t} (99 t - 88) = 99

= 88 \cdot \frac{1 \cdot ( 99 t - 88 ) - 99 t}{( 99 t - 88 ) ^{2}}

Vereinfache

88 \cdot \frac{1 \cdot ( 99 t - 88 ) - 99 t}{( 99 t - 88 ) ^{2}} : - \frac{64}{( 9 t - 8 ) ^{2}}

= - \frac{64}{( 9 t - 8 ) ^{2}}

\frac{d}{d x} (x^{\frac{2}{3}} (x - 2))

d er i v a t i v e ln (sec (2 x) + tan (2 x))

d er i v a t i v e f (x) = 3 x^{2} e^{x} + e^{x} (x^{3} + 9)

y \frac{d y}{d x} = \frac{4}{5} x

t an g e n t f (x) = 4 sec (x), at x = \frac{7 π}{6}