(\partial)/(\partial y)(2+3x+4y)

Lösung

\frac{\partial}{\partial y} (2 + 3 x + 4 y)

4

Schritte zur Lösung

\frac{\partial}{\partial y} (2 + 3 x + 4 y)

Behandle

x

als Konstante

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (2) + \frac{\partial}{\partial y} (3 x) + \frac{\partial}{\partial y} (4 y)

\frac{\partial}{\partial y} (2) = 0

\frac{\partial}{\partial y} (3 x) = 0

\frac{\partial}{\partial y} (4 y) = 4

= 0 + 0 + 4

Vereinfache

= 4

\int \frac{35}{1 - cos ( 7 x )} d x

\int \frac{x ^{3} - 7}{x} d x

\int arctan (\frac{sin ( x )}{1 + cos ( x )}) d x

d er i v a t i v e (\frac{x ^{2} + 4}{x ^{2} - 4})^{4}

t an g e n t y = \frac{4 x + 5}{x - 1}, (2, 13)