(\partial)/(\partial x)((x^2-1)/(x+1))

解答

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x + 1})

1

求解步骤

\frac{\partial}{\partial x} (\frac{x ^{2} - 1}{x + 1})

化简

\frac{x ^{2} - 1}{x + 1} : x - 1

= \frac{\partial}{\partial x} (x - 1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) - \frac{\partial}{\partial x} (1)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (1) = 0

= 1 - 0

化简

= 1

y^{^{''}} + 2 y^{^{'}} + y = \frac{- 18.5 e ^{- t}}{t ^{2} + 1}

\int cos (3 x) sin (3 x) d x

\frac{\partial}{\partial x} (7 + ln (x y - 9))

\frac{d}{d y} (e^{x} cos (y))

\frac{\partial}{\partial x} (\frac{26}{( 2 + x ^{2} + y ^{2} )})