What is the derivative of 2x^2-5x+3 ?

The derivative of 2x^2-5x+3 is 4x-5

What is the first derivative of 2x^2-5x+3 ?

The first derivative of 2x^2-5x+3 is 4x-5

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\frac{d}{d x} (2 x^{2} - 5 x + 3)

4 x - 5

Solution steps

\frac{d}{d x} (2 x^{2} - 5 x + 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{2}) - \frac{d}{d x} (5 x) + \frac{d}{d x} (3)

\frac{d}{d x} (2 x^{2}) = 4 x

\frac{d}{d x} (5 x) = 5

\frac{d}{d x} (3) = 0

= 4 x - 5 + 0

Simplify

= 4 x - 5

f (x) = 2 tan^{2} (6 x)

C (t) = 0.0225 t e^{- 0.0467 t}

\frac{d}{d x} (\frac{- 11}{( x - 3 ) ^{2}})

\frac{d}{d x} (x^{2} \cdot sin (x^{3}))

\frac{d}{d x} (\frac{8 e ^{6 x}}{5 x + 2})

What is the derivative of 2x^2-5x+3 ?
The derivative of 2x^2-5x+3 is 4x-5
What is the first derivative of 2x^2-5x+3 ?
The first derivative of 2x^2-5x+3 is 4x-5