derivative y=-1.97x^2+0.51x+8.1

解答

导数

y = - 1.97 x^{2} + 0.51 x + 8.1

- 3.94 x + 0.51

求解步骤

\frac{d}{d x} (- 1.97 x^{2} + 0.51 x + 8.1)

使用微分加减法定则:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (1.97 x^{2}) + \frac{d}{d x} (0.51 x) + \frac{d}{d x} (8.1)

\frac{d}{d x} (1.97 x^{2}) = 3.94 x

\frac{d}{d x} (0.51 x) = 0.51

\frac{d}{d x} (8.1) = 0

= - 3.94 x + 0.51 + 0

化简

= - 3.94 x + 0.51

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