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Popular >

area y=x+20,y=x^2

Solution

area

y = x + 20, y = x^{2}

Solution

\frac{243}{2}

+1

Decimal

121.5

Solution steps

Apply the area formula:

\int_{- 4}^{5} x + 20 - x^{2} d x

Solve

\int_{- 4}^{5} x + 20 - x^{2} d x : \frac{243}{2}

The area is:

= \frac{243}{2}

Graph

Popular Examples

integral of (1+2x)^{-2}

\int (1 + 2 x)^{- 2} d x

y^{''}e^{ax}-2a^2ye^{ax}=0

y^{^{''}} e^{a x} - 2 a^{2} y e^{a x} = 0

tangent of f(x)=sqrt(3x+7),\at x=6 tangent of

f (x) = 3 x + 7, at x = 6

derivative of (1-3x)/(6+x)derivative of

\frac{1 - 3 x}{6 + x}

derivative of f(x)= 1/((x+1)^2)derivative of

f (x) = \frac{1}{( x + 1 ) ^{2}}

Frequently Asked Questions (FAQ)

What is area y=x+20,y=x^2 ?
The answer to area y=x+20,y=x^2 is 243/2