derivative of 1/(3x^2-5/(2x))

Lösung

\frac{d}{d x} (\frac{1}{3 x ^{2}} - \frac{5}{2 x})

- \frac{2}{3 x ^{3}} + \frac{5}{2 x ^{2}}

Schritte zur Lösung

\frac{d}{d x} (\frac{1}{3 x ^{2}} - \frac{5}{2 x})

Wende die Summen-/Differenzregel an:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{1}{3 x ^{2}}) - \frac{d}{d x} (\frac{5}{2 x})

\frac{d}{d x} (\frac{1}{3 x ^{2}}) = - \frac{2}{3 x ^{3}}

\frac{d}{d x} (\frac{5}{2 x}) = - \frac{5}{2 x ^{2}}

= - \frac{2}{3 x ^{3}} - (- \frac{5}{2 x ^{2}})

Vereinfache

= - \frac{2}{3 x ^{3}} + \frac{5}{2 x ^{2}}

x^{2} y^{^{'}} - 4 x y = sin (2 x) x^{6}

\frac{d}{d x} (a + b x)

\frac{d}{d x} (\frac{2 x e ^{x}}{x ^{2} + 1})

\int 7 x^{2} sin (2 x) d x

k = 1 \sum \infty (\frac{1}{2})^{k}