(\partial)/(\partial y)(-4e^xcos(yz))

解答

\frac{\partial}{\partial y} (- 4 e^{x} cos (yz))

4 e^{x} z sin (yz)

求解步骤

\frac{\partial}{\partial y} (- 4 e^{x} cos (yz))

将

x, z

视为常数

将常数提出:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 e^{x} \frac{\partial}{\partial y} (cos (yz))

使用连锁律:

- sin (yz) \frac{\partial}{\partial y} (yz)

= - sin (yz) \frac{\partial}{\partial y} (yz)

\frac{\partial}{\partial y} (yz) = z

= - 4 e^{x} (- sin (yz) z)

化简

= 4 e^{x} z sin (yz)

\frac{d}{d x} (1 + x^{2} + x^{2} 1 + x^{2})

\int (5 e^{2 x} + \frac{1}{x}) d x

\frac{d}{d x} (sin (k t))

d er i v a t i v e f (x) = (5 + 2 x) e^{- 3 x}

\frac{d}{d x} (2 \cdot e^{2 x})