(dy)/(dt)=-3/(4sqrt(t))

Lösung

\frac{d y}{d t} = - \frac{3}{4 t}

y = - \frac{3}{2} t + c_{1}

Schritte zur Lösung

\frac{d y}{d t} = - \frac{3}{4 t}

Ersetze

\frac{d y}{d t}

mit

y^{'} (t)

y^{^{'}} (t) = - \frac{3}{4 t}

Wenn

f^{^{'}} (x) = g (x)

dann

f (x) = \int g (x) d x

y = \int - \frac{3}{4 t} d t

\int - \frac{3}{4 t} d t = - \frac{3}{2} t + c_{1}

y = - \frac{3}{2} t + c_{1}

\frac{\partial}{\partial x} (- \frac{2 x}{3 y})

y^{^{'}} = \frac{2 x}{1 + 2 y}, y (2) = 1

\int_{1}^{\infty} e^{- s t} d t

in v erse l a pl a ce \frac{1}{( s ^{2} + 1 ) ( s ^{2} + 4 )}

x (\frac{d y}{d x}) = \frac{( 1 - 4 y ^{2} )}{3 y}