y^{''}-2y^'=6e^{2x}

Lösung

y^{^{''}} - 2 y^{^{'}} = 6 e^{2 x}

y = c_{1} e^{2 x} + c_{2} + 3 x e^{2 x}

Schritte zur Lösung

y^{''} (x) - 2 y^{'} (x) = 6 e^{2 x}

Solve linear ODE:

y = c_{1} e^{2 x} + c_{2} + 3 x e^{2 x}

y = c_{1} e^{2 x} + c_{2} + 3 x e^{2 x}

\int \frac{9 x ^{2} + 6 x + 9}{x ^{3} - 1} d x

l a pl a ce t r an s f or m e^{2 t} sin (2 t j)

d er i v a t i v e y = c cos (t) + t^{2} sin (t)

\frac{\partial}{\partial y} (x + 2 y + 1)

l a pl a ce t r an s f or m 6 cos (4 t - 1)