y^{''}+y=sin(x)

Lösung

y^{^{''}} + y = sin (x)

y = c_{1} cos (x) + c_{2} sin (x) - \frac{x cos ( x )}{2}

Schritte zur Lösung

y^{''} (x) + y = sin (x)

Solve linear ODE:

y = c_{1} cos (x) + c_{2} sin (x) - \frac{x cos ( x )}{2}

y = c_{1} cos (x) + c_{2} sin (x) - \frac{x cos ( x )}{2}

\int_{0}^{1} 40 \frac{1}{x ^{p}} d x

\int (x + 2) 3 x^{2} + 4 x + 2 d x

\int \frac{( ( ( x ) + 1 ) \cdot ( x - 1 ) )}{( x )} d x

t an g e n t f (x) = x^{2} + 2, (- 2, 6)

\int 2^{x - 1} d x