What is (\partial)/(\partial y)(3x^2+2xy) ?

The answer to (\partial)/(\partial y)(3x^2+2xy) is 2x

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(\partial)/(\partial y)(3x^2+2xy)

\frac{\partial}{\partial y} (3 x^{2} + 2 x y)

2 x

Solution steps

\frac{\partial}{\partial y} (3 x^{2} + 2 x y)

Treat

x

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial y} (3 x^{2}) + \frac{\partial}{\partial y} (2 x y)

\frac{\partial}{\partial y} (3 x^{2}) = 0

\frac{\partial}{\partial y} (2 x y) = 2 x

= 0 + 2 x

Simplify

= 2 x

\frac{d}{d a} (sin^{3} (a) + cos^{3} (a))

f (x) = \frac{1}{5 + 2 x}, (2, \frac{1}{9})

f (x) = 3 x^{2} - 2

\int \frac{3 y ^{4} + 3 y ^{2} - 1}{y ^{3} + y} d y

\frac{d}{d y} (y (y - sin (x)))

What is (\partial)/(\partial y)(3x^2+2xy) ?
The answer to (\partial)/(\partial y)(3x^2+2xy) is 2x